Bo Lehnert Correcting M.W. Evans' Distortions

 Betreff:
        The dark spot
     An:
        G.W. Bruhn
 

Dear Gerhard,

  Der alte Esel hat es ganz gut abgefressen! I completely agree with the statement in the attachment of
your e-mail of July 7 at 21:21. In all the papers of my theory the results are based on the Lorenz gauge.

  During the coming ten days I will be out of my institute.

With best regards,

Bo  

Dear Bo,

since I'm not satisfied with the dubious situation concerning your paper from 1997 with S. Roy I've done some archaeology - following the German saying: Kaum ist über eine Sache Gras gewachsen, kommt ein alter Esel daher und frisst es wieder ab! (Let me know if I shall translate it): So now the old donkey will tell you what he has found when studying your old paper (attached):

This is the dark spot in your paper (see also my detailed explanation below) that was the cause of all trouble:

equations which yield

                ∇²(A, ^iΦ/_c) = − μ_o (j, icρ).                                       (7)

When combined with Lorentz condition, this gives

                div A + ¹/_c² ^∂Φ/_∂t = 0                                                (8)

. . .

However, the reader Myron - instead of interpreting this obvious obscurity in your paper as a new source of energy - should have attempted to use his mind and repair the gap.

So we see, how a tiny obscurity leads to great "inventions". What I cannot understand up to now is that no one of the 15 co-authors became suspicious and warned Myron not to publish such nonsense.

I don't know whether I should post my remarks below on my website. That depends on Myron's behavior. Better you could convince Myron that this whole story about the Energy from Vacuum was his fault and in no way mine.

Best regards

Gerhard

2.1 Maxwell Equations Modified by Non-zero Electric Field Divergence

The extended field equations in vacuo become [5-7,9]

                curl B = j + ε_o ^∂E/_∂t                                     (1)

                curl E = ¹/_c² ^∂B/_∂t                                         (2)

                j = ρ C                                                         (3)

in S.I. units. Here B and E are the magnetic and electric fields, j is the current density and ρ is the charge density

Then

                div E = ^ρ/_εo                                                 (4)

                div B = 0 , B = curl A                                 (5)

                E = − Ñ Φ − ^∂A/_∂t                                      (6)

Now,

                ∇ · (j , icρ) = 0

when ∇ = (^∂/_∂x, ^∂/_∂y, ^∂/_∂z, , ^∂/_ic∂t),

where (j , icρ) is a four vector. The potentials A and Φ are derived from the sources j and ρ through the above equations which yield

                ∇²(A, ^iΦ/_c) = − μ_o (j, icρ).                 (7)

When combined with Lorentz condition, this gives

                div A + ¹/_c² ^∂Φ/_∂t = 0                                (8)