Last Update: Sept 18, 2005, 08:00 pm
The definition of covariant derivatives is not uniquely determined. S.M. Carroll [2] used the well known tetrad identity
(1) ∂ρ qaμ + ωaρs qsμ − Γσρμ qaσ = 0
to define a covariant derivative Ñρ that admits interpreting of (1) as Ñρ qaμ = 0 : Carroll defines
(2) Ñρ qaμ := ∂ρ qaμ + ωaμs qsρ − Γσρμ qaσ .
In the following we'll speak here of Ñρ as of the "Carroll derivative" for matter of distinction.
Using the Carroll derivative we have the "tetrad postulate"
(3) Ñρ qaμ = 0
The rule: Each upper Latin index (e.g. at qa· ) causes an additive term + ωaμb qb· , while a lower Latin index (e.g. at q·a) gives rise to the additive term − ωaμb q·a. Greek indices have to be treated as usual [2; (3.1),(3.12)]
Example:
(4) Ñρ qμa := ∂ρ qμa − ωsρa qμs + Γμρσ qσa .
Let η = (ηab) := diag(−1, 1, 1, 1) be the Minkowski matrix. Then due to the constancy of each ηab we obtain
(5) Ñρ ηab = ∂ρηab − ωsρa ηsb − ωsρb ηas = − ωsρa ηsb − ωsρb ηas = − ωb,ρa − ωa,ρb .
M.W. Evans applies the Carroll derivative in the following way: He wants to calculate Ñρ gμν by referring to the equation gμν = ηab qaμ qbν. Using the Leibniz rule Evans concludes due to (3)
(6) Ñρgμν = Ñρ (ηab qaμ qbν) = (Ñρηab) qaμ qbν + 0 + 0 .
Here he erroneously assumes the derivative Ñρ of a constant term ηab to be ZERO (also - among other errors - e.g. on [1; p.46 and p.70] where the Minkowski matrix is unwritten to have an elegant notation) Ñρηab = 0, which would prove the metric compatibility from the tetrad identity.
However, the correct result is due to (4)
(7) Ñρgμν = Ñρ (ηab qaμ qbν) = − (ωb,ρa + ωa,ρb) qaμ qbν = − (ων,ρμ + ωμ,ρν)
which differs from zero in general.
Evans should have recognized his conclusion to be wrong, since one can get the desired result directly also by evaluating :
(8) Ñρgμν = ∂ρgμν − Γλρμgλν − Γλρνgμλ
where the term ∂ρgμν = ∂ρ(ηab qaμ qbν) is to be calculated with the Leibniz rule of partials:
Ñρ gμν
=
∂ρ gμν
−
Γλρμ
gλν
−
Γλρν
gμλ
=
ηab
(∂ρqaμ) qbν
+
ηab
qaμ (∂ρqbν)
−
Γλρμ
gλν
−
Γλρν
gμλ
=
[ηab
(∂ρqaμ) qbν
−
Γλρμ
gλν]
+
[ηab
qaμ (∂ρqbν)
−
Γλρν
gμλ]
=
ηab
(∂ρqaμ
−
Γλρμqaλ)
qbν
+
ηab
qaμ (∂ρqbν
−
Γλρν
qbλ)
By using the tetrad identity (1) we obtain finally
Ñρ gμν
=
ηab
[(∂ρqaμ
−
Γλρμqaλ)
qbν
+
qaμ (∂ρqbν
−
Γλρν
qbλ)]
=
− ηab
(ωaρc
qcμ
qbν
+ ωbρc
qaμ
qcν)
=
− ηab
ωaρc
(qcμ
qbν
+
qbμ
qcν)
=
−
ωaρc
(qcμ
ηab qbν
+
ηabqbμ
qcν)
=
−
ωaρc
(qcμ
qσa gσν
+
qcν
qσa gσμ)
=
−
ωaρc
qσa
(qcμ
gσν
+
qcν
gσμ)
=
−
ωσρc
(qcμ
gσν
+
qcν
gσμ)
=
−
(ωσρμ
gσν
+
ωσρν
gσμ)
=
−
(ων,ρμ
+
ωμ,ρν).
in accordance with Equ.(7). Therefore we have
Remark Evans reference [2] to the covariant derivative to be used is ambiguous. S.M. Carroll gives two different definitions: The "Carroll definition" at [2; p.91] and the "usual" one for D at [2; p.56 (3.1) and p.58 (3.12)]. At [1; p.46 (2.182) we find the application of the usual definition [2; p.56 (3.1)]
(4') Dν qμa := ∂ν qμa + Γμνλ qλa
in Evans' notation with suppressed Latin indices
Dν qμ := ∂ν qμ + Γμνλ qλ (2.182)
With the extended equation (4') instead of (2.182) we obtain
Dρ gμν
= Dρ (ηab
qμaqνb)
=
ηab
[(Dρqaμ) qbν
+ qaμ (Dρqbν)]
=
ηab
[(∂ρ qμa
+
Γμρλ qλa)
qνb + qμa
(∂ρ qνb
+
Γνρλ qλb)].
Here the analoguous equation to the tetrade identity (1), the equation
(1') ∂ρ qμa − ωsρa qμs + Γμρσ qσa = 0
can be used to obtain
= − ηab
(ωsρa qμs
qνb
+
ωsρb qνs qμa)
= − ηab
(ωμρa
qνb
+
ωνρb qμa)
= −
(ωμρν
+
ωνρμ) .
The reader is kindly asked to prove the analoguous equation
(7') Dρgμν = − (ων,ρμ + ωμ,ρν),which agrees with (7) though different covariant differential operators Ñρ and Dρ were used.
[1]
M.W. Evans, Generally Covariant Unified Field Theory,
the geometrization of physics,
http://www.aias.us/Comments/Evans-Book-Final.pdf
[2]
Sean M. Carroll, Lecture Notes on General Relativity,
http://arxiv.org/pdf/gr-qc/9712019