^{Last update: 21.08.2004 19:00}

(Quotations from M.W. Evans handwritten "REFUTATION"
[6]
in **
black**,
my remarks in **blue**.)

Some months ago, in the sequel of the esoteric DGEIM-Congress at Stuttgart
in October 2003, where the work of the AIAS group was praised, I wrote a
refutation
[5]
of a basic statement of AIAS director Myron W. Evans. Evans replied with
a handwritten philippic
[6]
against me accusing me of *several elementary blunders*
(among other things).
So he gave rise to check the claims of his publication
[6]
which will be done here
below. In order to give opportunity to the reader to read Evans' "REFUTATION" as a
whole I have attached it here as a htm-copy in
Appendix 2.
References to that text are given by links.

For the reader not
familiar with Evans' basics I can say that with a few words: Instead of the
Cartesian basis vectors **i**,
**j**, **k** Evans introduces a unitary basis consisting of certain complex
basis vectors **e**^{(1)}, **e**^{(2)}, **e**^{(3)}.
The *elementary* rules in the consequence of that coordinate transform are
summed up in
Appendix 1.

I shall refer to formulas in Appendix 1
by the equation labels (A. ..).
Vectors are denoted by bold face letters, e.g. the basis vectors **i**,
**j**, **k**. The letter i in light face is the imaginary unit.

In the course of the actual email discussion Evans referred to the book [9]
to justify his calculations in Appendix 2. He wrote:

*
«. . . my definition of circular polarization is the
same as that in a standard text such as J. D. Jackson, "Classical Electrodynamics"
(Wiley third edition, 1999, page 299, eq. (7.20)).»*

So I give some quotes of that pages in Appendix 3. It will turn out that Evans' definition given in his REFUTATION is completely incompatible to Jackson's description of circular polarization.

Appendix 4 contains some simple questions to M. Evans on the basis of Appendix 3 he refused to reply to in the email discussion.

The first elementary error in Bruhn's claims occurs in his equations equs. (2.3) and (2.4) .

**Check 1**

Let's quote some eqs. of my paper [5]. Due to the literature
(e.g.
[7; p.188], [8; p.702 f.]) a vector

**B** = **i** B_{x} __+__ **j** B_{y}

of left (+ = L) and right (− = R) circular polarization around the z-axis (direction **k**)
is given by choosing

(2.1)
B_{x} = B_{0} cos Φ
and
B_{y} = B_{0} sin Φ .

Then due to Evans' basic equations (A.3) and (A.5)
we obtain the components of **B**
relative to the cyclic basis of the vectors **e**^{(r)} (r=1,2,3):

(2.3)
**B**_{R}^{(1)}
= **e**^{(1)} B^{(0)} e^{iΦ},
**B**_{R}^{(2)}
= **e**^{(2)} B^{(0)} e^{−iΦ}

and

(2.4)
**B**_{L}^{(1)}
= **e**^{(1)} B^{(0)} e^{−iΦ},
**B**_{L}^{(2)}
= **e**^{(2)} B^{(0)} e^{iΦ}

**Result 1**

There is no doubt about it, the equations
(2.3) and (2.4)
describe right
and left handed circular polarization *correctly*.

It is easy to show that Bruhn has made an elementary blunder because when we add his equations equs. (2.3) and (2.4) we obtain

**B**_{L}^{(1)} + **B**_{R}^{(1)}
= B^{(0)} **e**^{(1)}
(e^{i}^{Φ} + e^{−iΦ})

= B^{(0)} 2^{−1/2} (**i **− i **j**)
(e^{i}^{Φ} + e^{−iΦ})
(1)

= B^{(0)} 2^{−1/2 }(**i **− i **j**) cos Φ
(2)

However, it is well known that the sum of left and right circular
polarization is __linear__ polarization.
Bruhn’s equ. (2) is still *circular polarization*.

**Check 2**

**Preliminary remark** (of minor importance):

In (2) a factor 2 is missing. Hence we have
correctly

**B**_{L}^{(1)} + **B**_{R}^{(1)}
= B^{(0)} 2^{1/2 }(**i **− i **j**) cos Φ
(2')

We shall use (2') instead of (2) below.

Due to the rule
(A.7),
**a**^{(2)} = **a**^{(1)}*, we obtain from (2')

**B**_{L}^{(2)} + **B**_{R}^{(2)}
= B^{(0)} 2^{1/2 }(**i** + i **j**) cos Φ

while
**B**^{(3)} = **0** holds by assumption.

Hence from
**B** = **B**^{(1)} + **B**^{(2)}
+ **B**^{(3)}
(cf. (A.2)) we obtain

**B**
= 2 B^{(0)} 2^{1/2 }**i** cos Φ
= **i 2 **B_{0} cos Φ .

**Result 2**

**B** is a *real* vector in *constant* direction **i**
oscillating proportionally to cos Φ. Hence **B** is clearly *linear polarized*.

The correct way to represent *left and right
circular polarization* is as follows

**B**_{L}^{(1)}
= 2^{−1/2} (B_{x} **i** − i B_{y} **j**)
e^{iΦ}
(3)

**B**_{R}^{(1)}
= 2^{−1/2} (B_{x} **i** + i B_{y}
**j**) e^{iΦ}
(4)

**Check 3**

The superscript ^{(1)} of the notations **B**_{L}^{(1)}
and **B**_{R}^{(1)} in the equs. (3) and (4)
means that the **e**^{(1)}-components of the vectors
**B**_{L} and **B**_{R} will be defined by the right sides
of the equs. (3) and (4). Hence e.g. the right side of equ. (3) must be parallel to the basis vector
**e**^{(1)} (cf. equs. (1) and (2), where the
**e**^{(1)}-component
of **B**_{L} + **B**_{R} is defined by a vector
| | **i** − i **j**, i.e. | | **e**^{(1)}).
Therefore the equs. (3) and (4) would imply

B_{x} **i** __+__ i B_{y} **j** | |
**i** __+__ i **j**,

i.e. B_{x} = B_{y}. The choice in my article [5; (2.1)] which Evans is referring to
(or also Jackson's book [9; (7.21)]) yields

B_{x} = B_{0} cos Φ
and
B_{y} = B_{0} sin Φ ,

B_{x} = B_{y} hence implies cos Φ = sin Φ.
That contradicts the variability of Φ and is impossible.

**Result 3**

The definition of
**B**_{L}^{(1)} and **B**_{R}^{(1)}
by the equs. (3) and (4) is inconsistent.

Add (3) and (4) to obtain

**B**_{L}^{(1)} + **B**_{R}^{(1)}
= 2^{1/2} B_{x}** i **e^{iΦ
}(5)

which is *linear polarization as required.*

**Check 4**

By an argumentation analogously to
Check 3.
__
we see that
for B___{x} ≠ 0 equ. (5) would imply

**i** − i **j** | | **i**

which is a contradiction, regardless of the rest of Evans' claim.

**Result 4**

Equ. (5) is inconsistent.

From equ. (3) we see that the left c.p. wave is

**B**_{L}^{(1)}
= 2^{−1/2} (B_{x} cos Φ
**i**
+ B_{y} sin Φ
**j**)
(6)

From equ. (4) we see that the right c.p. wave is

**B**_{R}^{(1)}
= 2^{−1/2} (B_{x} cos Φ
**i** − B_{y} sin Φ
**j**)
(7)

Equ. (6) is Bruhn’s equ. (4.2) and equ. (7) is Bruhn’s equ. (4.1).

**Check 5**

By an argumentation analogously to
Check 3.
we see that
(6) would imply

**i** − i **j** | |
**i** cos^{2}Φ + **j** sin^{2}Φ

which is a contradiction since the left side has an imaginary part while
the right side is real.

An analoguos argumentation holds for equ. (7).

Concerning Evans' last remark we quote the equations (4.1-2)
from our refutation [5]:

(4.1)
**B**_{R} = B_{0} (**i** cos Φ + **j** sin Φ)
and
(4.2)
**B**_{L}
= B_{0} (**i** cos Φ − **j** sin Φ).

Equ. (4.1) describes a right polarized wave and (4.2)
describes a left polarized wave.

Of course, the equations (4.1-2) are in accordance with the literature (cf. [7; p.188], [8; p.702 f.]).

**Result 5**

The equs. (6) and (7) are inconsistent.

This shows that my equations (3) and (4) give Bruhn’s own definitions of left and right handed c.p. in his equs. (4.1) and (4.2).

**Check 5**

As I have just shown Evans' equs.
(3) and (4)
are erroneous while my
(4.1) and (4.2) are correct since being
in accordance with the literature.

**Result 6**

Bruhn’s equs. (4.1) and (4.2) therefore contradict Bruhn’s equs. equs. (2.3) and (2.4), because when we add Bruhn’s equs. (4.1) and (4.2) we obtain linear polarization, but when we add equs. equs. (2.3) and (2.4) we obtain circular polarization.

**Check 7**

As we have remarked above the equs. (4.1) and (4.2)
give right and left polarization in accordance with the literature.
And the equations

(2.3)
**B**_{R}^{(1)}
= **e**^{(1)} B^{(0)} e^{iΦ},
**B**_{R}^{(2)}
= **e**^{(2)} B^{(0)} e^{−iΦ}

and

(2.4)
**B**_{L}^{(1)}
= **e**^{(1)} B^{(0)} e^{−iΦ},
**B**_{L}^{(2)}
= **e**^{(2)} B^{(0)} e^{iΦ}

are nothing but
the components of **B**_{R} and **B**_{L}
relative to the basis **e**^{(1)}, **e**^{(2)},
as can be shown by an elementary calculation. Hence there cannot be any contradiction
between these equations.

**Result 7**

An elementary calculation would show no contradiction
between these equations.

The glaring error in Bruhn’s claims occurs in
his equ. (4.5), were he asserts, that for linear polarization:

**B**^{(3)} = ? __+__ 2^{1/2} B^{(0)} **k**
(11)

**Check 8**

Evans' quotation of equ. (4.5) is *incorrect*: The correct quote is

(4.5)
**B**^{(3)} = **0
OR
B**

Hence (4.5) is valid, since Evans' assures the first alternative of that OR-statement to be true.

**Result 8**

Evans' Claim 8 is due to an incorrect quotation.

The B Cyclic theorem always applies to ** one** sense of
polarization.

**Check 8**

That claim is at least dubious. Since in 1994 Evans had declared in [2; p.69];

*"We assert therefore that in classical
electrodynamics there are three components ***B**^{(1)}*,
***B**^{(2)} *and*
**B**^{(3)}* of a travelling plane wave in vacuo.
These are interrelated in the circular basis by equation
[2; (2)]. The third component, the ghost field*

Equ. [2; (2)] are Evans’ cyclic
equations that were extended herewith by M. Evans himself to «waves in vacuo»
[2, p. 69] * without any restriction*.
And lateron he did never qualify that statement.
Thus: Evans’ cyclic equations could be thought to be valid for
the superposition of circularly polarized plane waves too. This was what I
have checked in my refutation [5] − with negative result.

Now in his "REFUTATION" [6] from 2004 Evans declares as a reply on my provocing paper [5] with restrictive intention

*"The B Cyclic theorem always applies to one sense of polarization."*

i.e. Evans' cyclic equations do not hold for linear polarization as a superposition of right and left handed circular polarization.

**Result 9**

Now, in 2004, M. Evans agrees with the result of my refutation [5].

All claims in Myron W. Evans' "REFUTATION" [6] have turned out to be erroneous or dubious at least. Therefore publications of that author should be read with greatest caution and scepticism.

[1]
M.W. Evans: The elementary static magnetic field of the photon, Physica B **182 **(1992)
227-236.

[2]
M.W. Evans: The photomagneton B**^**^{(3)} and its longitudinal ghost field
**B**^{(3)} of electromagnetism,
Foundations of Physics Letters, Vol. **7**, No. 1 (1994) 67 - 74.

[3]
M.W. Evans: The Enigmatic Photon, Vol. **5**, Kluwer Academic Publishers 1999,
ISBN 0-7923-5792-2

[4]
M.W. Evans e.a. : Explanation of the **M**otionless **E**lectromagnetic **G**enerator
(MEG) with O(3) Electrodynamics; Foundations of Physics Letters, Vol. **14**
No. 1 (2001)

[5]
G. W. Bruhn: Refutation of Myron W. Evans’ B^{(3)} field hypothesis

http://www2.mathematik.tu-darmstadt.de/~bruhn/B3-refutation.htm

[6]
M.W. Evans:
REFUTATION OF THE CLAIMS OF G. BRUHN (handwritten)

http://www2.mathematik.tu-darmstadt.de/~bruhn/abruhnrefutation.pdf

[7] W. Demtröder: Experimentalphysik 2; 2. Auflage, Springer Verlag 2002, ISBN 3-540-65196-9

[8] E. Schmutzer: Grundlagen der Theoretischen Physik Teil 1; 2. Auflage, BI Verlag 1989, ISBN 3-411-03145-X

[9] J.D. Jackson: Classical Electrodynamics; 3. Ed. , Wiley 1989, ISBN 0-471-30932-X

Circular basis (Cartesian unit vectors **i**, **j**, **k**, imaginary unit i)
:

(A.1)
**e**^{(1)}
= (**i** − i** j**)/2^{1/2},
**e**^{(2)}
= (**i** + i **j**)/2^{1/2},
**e**^{(3)}
= **k** .

Coordinate representations of all vectors **a**:

(A.2)
a_{x} **i** + a_{y}
**j** + a_{z} **k** = **a**
= a^{(1)}** e**^{(1)}
+ a^{(2)} **e**^{(2)}
+ a^{(3)}
**e**^{(3)}

Transformation rule for coordinates

(A.3)
a^{(1)}
= 2^{−1/2} (a_{x} **+** i a_{y}),
a^{(2)}
= 2^{−1/2} (a_{x} **−** i a_{y}),
a^{(3)}
= a_{z}.

(A.4)
|a^{(1)}|^{2} +|a^{(2)}|^{2}
+|a^{(3)}|^{2}
= a_{x}^{2}
+ a_{y}^{2} + a_{z}^{2}
= |**a**|^{2} .

Vector components of **a** relative to the circular basis

(A.5)
**a**^{(1)}
= a^{(1) }**e**^{(1)},
**a**^{(2)}
= a^{(2) }**e**^{(2)},
**a**^{(3)}
= a^{(3) }**e**^{(3)}.

The suffix * denotes the conjugate complex of the quantity where it is attached.

(A.6)
**e**^{(1)}*
= **e**^{(2)},
**e**^{(2)}*
= **e**^{(1)},
**e**^{(3)}*
= **e**^{(3)}

(A.7)
**a**^{(1)}* = **a**^{(2)},
**a**^{(2)}* = **a**^{(1)},
**a**^{(3)}*
= **a**^{(3)}

(A.8)
a^{(1)} = a^{(2)}*,
a^{(2)} = a^{(1)}*,
a^{(3)} = a^{(3)}*.

(A.9)
**e**^{(1)} × **e**^{(2)}
= i**e**^{(3)}*,
**e**^{(2)}×
**e**^{(3)}
= i **e**^{(1)}*,
**e**^{(3)}× **e**^{(1)}
= i **e**^{(2)}*.

** Remark**
The rules
(A.1-8) have an important consequence
that was not explicitly pointed out
in Evans' book [3]: The vector coordinates a

**a*** = **a**^{(1)}* + **a**^{(2)}* +**a**^{(3)}*
= **a**^{(2)} + **a**^{(1)} +**a**^{(3)} = **a**

which implies the reality of the coordinates a_{x}, a_{y}, a_{z}
by using (A.2) again.

(Copy of the handwritten original [6])

The relevant e-mail posting by G. Bruhn is appended. Bruhn posted it without my knowledge, and apparently it was an unrefereed document. Bruhn refers to none of my recent work which is now universally acclaimed and accepted. Here I comment on Bruhn's posting section by section.

__Section 1__

This is merely a quote by Bruhn of some of my earliest work on B^{(3)},
almost a decade ago.

__Section 2__

The first elementary error in Bruhn's claims occurs in his equations
equs. (2.3) and (2.4).

It is easy to show
that Bruhn has made an elementary blunder because when we add his
equations
equs. (2.3) and (2.4)
we obtain

**B**_{L}^{(1)} + **B**_{R}^{(1)}
= B^{(0)} **e**^{(1)}
(e^{i}^{Φ} + e^{−iΦ})

= B^{(0)} 2^{−1/2} (**i **− i **j**)
(e^{i}^{Φ} + e^{−iΦ})
(1)

= B^{(0)} 2^{−1/2 }(**i **− i **j**) cos Φ
(2)

However, it is well known that the sum of left and right circular
polarization is __linear__ polarization.
Bruhn’s equ. (2) is still *circular polarization*.

The correct way to represent left and right
circular polarization is as follows:

**B**_{L}^{(1)}
= 2^{−1/2} (B_{x} **i** − i B_{y}
**j**) e^{iΦ}
(3)

**B**_{R}^{(1)}
= 2^{−1/2} (B_{x} **i** + i B_{y}
**j**) e^{iΦ}
(4)

Add (3) and (4) to obtain

**B**_{L}^{(1)} + **B**_{R}^{(1)}
= 2^{1/2} B_{x}** i **e^{iΦ}
(5)

which is *linear polarization as required.*

In fact I have mentioned the chirality question in my writings many times (e.g. Adv. Chem. Phys. Vol. 85). This shows that Bruhn is almost completely ignorant of my work. The rest of Bruhn’s claim is sequentially erroneous, and furthermore, contains other elementary blunders.

__Section 3__

In this section, Bruhn quotes my well known B Cyclic Theorem.

__Section 4__

From equ. (3) we see that the left c.p. wave is

**B**_{L}^{(1)}
= 2^{−1/2} (B_{x} cos Φ
**i**
+ B_{y} sin Φ
**j**)
(6)

From equ. (4) we see that the right c.p. wave is

**B**_{R}^{(1)}
= 2^{−1/2} (B_{x} cos Φ
**i** − B_{y} sin Φ
**j**)
(7)

Equ. (6) is Bruhn’s equ. (4.2) and equ. (7) is Bruhn’s equ. (4.1).

This shows that my equations (3) and (4) give Bruhn’s own definitions of left and right handed c.p. in his equs. (4.1) and (4.2).

Bruhn’s equs. (4.1) and (4.2) therefore contradict Bruhn’s equs. equs. (2.3) and (2.4), because when we add Bruhn’s equs. (4.1) and (4.2) we obtain linear polarization, but when we add equs. equs. (2.3) and (2.4) we obtain circular polarization.

These errors already make nonsense of Bruhn’s unrefereed claim, but his
main error is to confuse what is meant by **B**^{(3)}.
I have written many times that **B**^{(3)}
is equal and opposite for left and right
handed circular polarization, and for this reason vanishes in linear
polarisation. Mathematically:

**B**_{R}^{(3)}
= − ^{i}/_{B(0)}
**B**_{R}^{(1)}
× **B**_{R}^{(2)}
= . . .
= i^{2
}B^{(0)} **k**
= − B^{(0)} **k**
(8)

**B**_{L}^{(3)}
= − ^{i}/_{B(0)}
**B**_{L}^{(1)}
× **B**_{L}^{(2)}
= . . .
= − i^{2} B^{(0)} **k** =
B^{(0)} **k**
(9)

Thus:

**B**_{R}^{(3)}
= − **B**_{L}^{(3)}
(10)

The glaring error in Bruhn’s claims occurs in his equ. (4.5), were he asserts, that for linear polarization:

**B**^{(3)} = ? __+__ 2^{1/2} B^{(0)} **k**
(11)

The reason for the erroneous equ. (11) appears to be confusion about
what is meant by **B**^{(3) }. The latter is well-defined in my work as
existing for one photon. One photon is either left handed, in which case we
obtain equ. (9) or right handed, in which case we obtain equ. (8).
If we superimpose
one left handed photon with one right handed photon we obtain

**B**^{(3)} = **B**_{R}^{(3)}
+ **B**_{L}^{(3)} = **0**.

The B Cyclic theorem always applies to ** one** sense of
polarization.

Therefore the claim by Bruhn is false, and unreasonable, i.e. it is made in ignorance of the literature.

J. D. Jackson's Chapter 7 from [9] on polarized plane waves

Firstly a quote from an Evans' email:

*«I have briefly glanced at your "second refutation". It is nonsense. For example you claim that my definition of circular polarization leds to a
contradiction. However, my definition of circular polarization is the same as that in a standard text such as J. D. Jackson, "Classical Electrodynamics" (Wiley third
edition, 1999, page 299, eq. (7.20)). Jackson is no supporter of AIAS but is a good scholar. For your further information the right and left circularly polarized waves
are defined in detail by Jackson on page 300 ff. ...»*

At the end of this appendix we shall compare both Evans' and Jackson's definitions.

. . . the most general homogeneous plane wave . . .

**E**(**x**,t)
= (**e**_{1} E_{1}
+ **e**_{2} E_{2}) e^{− iΦ}
where
Φ = ωt − **k·x**
(7.19)

with the Cartesian basis vectors
**e**_{1},**e**_{2},**k**,
c.f. Fig. 7.1, p.297
(identical with the usual
Cartesian basis denoted by **i**, **j**, **k**).

We should realize that (7.19) is *not the original wave vector* which is real:
The imaginary part was supplemented in order to get arithmetical advantages and has no physical meaning.

If E_{1} and E_{2} have the *same phase* (7.19) represents a
*linearly polarized* wave. . . .

. . . *circular polarization*.
Then E_{1} and E_{2} have the same magnitude,
but differ in phase by 90°.

**E**(**x**,t)
= E_{0} (**e**_{1} __+__ i **e**_{2})
e^{− i
Φ}
where
Φ = ωt − **k·x**
(7.20)

. . . while **e**_{1} and **e**_{2} are in the x and y directions,
respectively. Then the components of the actual electric field,
obtained by taking the * real part* of (7.20), are

E_{x} = E_{0} cos Φ

(7.21)

E_{y} = __+__ E_{0} sin Φ

... For the upper sign (**e**_{1} + i **e**_{2})
the rotation is counterclockweise
when the observer is facing into the oncomming wave.
This wave is called *left circularly polarized* in optics. ...

For the lower sign (**e**_{1} − i **e**_{2})
the rotation of **E** is clockwise when looking into the wave is *right circularly
polarized* (optics) ...

. . . We introduce the complex orthogonal unit vectors:

**e**_{+}
= 2^{−1/2} (**e**_{1} __+__ i **e**_{2})
(7.22)

. . . Then a general representation, equivalent to (7.19), is

**E** =
(E_{+} **e**_{+}
+ E_{−} **e**_{−}) e^{− iΦ}
(7.24)

where E_{+} and E_{−} are complex amplitudes.

__Examples__

For the pupose of comparison with Evans' formulas we replace Jackson's notation with that one
of Evans:

**e**_{1} → **i**,
**e**_{2} → **j**,
**e**_{−} → **e**^{(1)},
**e**_{+} → **e**^{(2)},
**E** → **B**, . . .

A linearly polarized wave is given if the quotient B_{+}/B_{−}
is real, in which case, by changing the coordinate system, we can attain the
standard form

**B**_{lin} = B_{0} **i** e^{− iΦ}

with some real constant B_{0}.
Circularly polarized waves can be described by means of the complex basis vectors
**e**^{(1)} and **e**^{(2)}:

**B**_{L}^{(1)}
= B_{0} **e**^{(1)} e^{− iΦ}

is Jackson's standard form of a left circularly polarized wave, strictly speaking,
its **e**^{(1)}-component, while

**B**_{R}^{(2)} = B_{0} **e**^{(2)} e^{− iΦ}

is Jackson's standard form of a right circularly polarized wave, more exactly, its
**e**^{(2)}-component. The **e**^{(1)}-component of
**B**_{R} can be obtained by
taking the conjugate complex expression, i.e.

**B**_{R}^{(1)}
= B_{0} **e**^{(1)} e^{iΦ} .

For a comparison we have to take into account that *the last representations are not
the original real wave vectors* but are the result of complex supplementation.
However, it is
easy to reconstruct the original physical wave vectors: We merely have to take the
corresponding real parts.
By doing so we obtain

**B**_{lin}^{phys}
= B_{0} **i** cos Φ for linear polarization,

**B**_{L}^{phys}
= Re {B_{0} **e**^{(1)} e^{− iΦ}}
= B_{0} (**i** cos Φ − **j** sin Φ)/2^{1/2}
for left circular polarization

and

**B**_{R}^{phys}
= Re {B_{0} **e**^{(2)} e^{iΦ}}
= B_{0} (**i** cos Φ + **j** sin Φ)/2^{1/2}
for right circular polarization.

We have to compare Jackson's standard forms of polarized waves with that
ones given by Evans in his
"REFUTATION" equs. (3-5):

Evans
Jackson

**B**_{L}^{(1)}
= 2^{−1/2} (B_{x} **i** − i B_{y}
**j**) e^{iΦ} ,
**B**_{L}^{(1)}
= B_{0} **e**^{(1)} e^{− iΦ}

**B**_{R}^{(1)}
= 2^{−1/2} (B_{x} **i** + i B_{y}
**j**) e^{iΦ} ,
**B**_{R}^{(1)}
= B_{0} **e**^{(1)} e^{iΦ} .

Let's quote Evans again:
*
« . . . my definition of circular polarization is the
same as that in a standard text such as J. D. Jackson, "Classical Electrodynamics" (Wiley third
edition, 1999, page 299, eq. (7.20)).»*

**No, Dr. Evans, not at all. There is a considerable disagreement between Evans' and Jackson's formulas.
Possibly, Evans' formulas are erroneous due to rather simple errors.
However, Evans intended to give a refutation of my calculations. For that purpose
Evans should have proceeded much more carefully.**

Additionally I can state that my formulas (2.3) and (2.4) for circular polarization completely agree with the Jackson's formulas above.

Instead of replying to the questions Evans broke off the discussion:

Quotation from Evans' email:
*«The simple questions you are asking are irrelevant to the definition of the
conjugate product that I and many others habitually use and irrelevant to
physics. So I intend not to answer them because you are confused, and your questions
will cause further confusion. What you are doing has been attempted many
times before, to disingenuously set up a false paradigm , or to set up a straw man to
knock over.
I conclude that you know nothing about the inverse Faraday effect and nothing about
electrodynamics.»*

1.1) Do you admit, that the *physical* vectors **B**_{lin} for linear polarization,

**B**_{L} for left-handed and **B**_{R} for right-handed polarization
are *real* vectors?

**B**_{L} = B_{0}
(**i **cos Φ− **j** sin Φ)

**B**_{R}
= B_{0} (**i** cos Φ + **j** sinΦ)
(Φ = ωt − **k·x**)

**B**_{lin}
= 2 B_{0} **i** cos Φ

(Y / N)

1.2)
Due to Jackson's equs. (7.19) and (7.20)

(J.D. Jackson: Classical Electrodynamics 3.Ed. 1999)

(with exchange of characters
**E** → **B** and **e**_{1},
**e**_{2}** → i**, **j**), e.g.

**B(x**,t)
= B_{0} (**i +** i

the Jackson-vectors have

Jacksons' equs. do

formulas in 1.1.

(Y / N)

1.3) Can you explain the physical meaning and origin of these imaginary parts?

(Y / N)

If Y, please, give an explanation.

2) Why just these imaginary parts? I know other ones that would fit.

3.1) Do you know that all physical vectors **a** that fulfil your

basic rules
in Vol. 5 of your photon-books must be real?
**a = a***

(Y / N)

3.2) Which of the vectors **B** defined in 1.1 or 1.2 could fulfil

the Evans basic rules?

(1.1 / 1.2 / both)

4) Consider three important polarized waves using the *real* representations

of the wave vector **B** according to
Jackson (7.21):

Left circular:
(L)
B_{x} = B_{0} cos Φ,
B_{y} = − B_{x} = − B_{0} sin Φ

Right circular: (R)
B_{x} = B_{0} cos Φ,
B_{y} = + B_{x} = + B_{0} sin Φ

Linear in x-dir.: (lin) B_{x}
= 2 B_{0} cos Φ,
B_{y} = 0

Addition yields (L) + (R) = (lin).

Now insert that into Evans' equs. [Enigm.Photon Vol 5; ((1.1.6)]
(cf. Evans basic rule A.3)

for circular vector coordinates which are

B^{(1)} = (B_{x} − i B_{y})/sqr(2),
B^{(2)} = (B_{x} + i B_{y})/sqr(2)

to obtain

(L)
B^{(1)} = B_{0} e^{−iΦ}/sqr(2),
B^{(2)} = B_{0} e^{+iΦ}/sqr(2),

(R)
B^{(1)} = B_{0} e^{+iΦ}/sqr(2),
B^{(2)} = B_{0} e^{−iΦ}/sqr(2),

(lin) B^{(1)} = B^{(2)} = sqr(2) B_{0} cos Φ.

That result contradicts Evans' formulas in his
"REFUTATION" equs. (3-5)

who claims

(L)
**B**^{(1)}
= (B_{x} **i** − i B_{y} **j**) e^{iΦ}/sqr(2),

(R)
**B**^{(1)}
= (B_{x} **i** + i B_{y}**j**) e^{iΦ}/sqr(2),

(lin)
**B**^{(1)} = sqr(2) B_{x} **i** e^{iΦ}.

One should have [Enigm.Photon Vol 5; (1.1.5)]
(cf. A.5)

**B**^{(1)} = B^{(1)} **e**^{(1)}

e.g. in the case (lin) we obtain the *different* results for **B**^{(1)}:

sqr(2) **e**^{(1)}
B_{0} cos Φ

and

sqr(2) B_{x} **i** e^{iΦ}
= sqr(2) **i** B_{0} e^{iΦ} cos Φ

respectively.

Thus, there is a contradiction *within* Evans' original formulas.

Should there exist "ghosts" that have been produced by using

the "Jackson-method" of complex supplementation?

(Y / N)

If N: *Where* is the error?
(???)