Last update: 21.08.2004 19:00
(Quotations from M.W. Evans handwritten "REFUTATION" [6] in black, my remarks in blue.)
Some months ago, in the sequel of the esoteric DGEIM-Congress at Stuttgart in October 2003, where the work of the AIAS group was praised, I wrote a refutation [5] of a basic statement of AIAS director Myron W. Evans. Evans replied with a handwritten philippic [6] against me accusing me of several elementary blunders (among other things). So he gave rise to check the claims of his publication [6] which will be done here below. In order to give opportunity to the reader to read Evans' "REFUTATION" as a whole I have attached it here as a htm-copy in Appendix 2. References to that text are given by links.
For the reader not
familiar with Evans' basics I can say that with a few words: Instead of the
Cartesian basis vectors i,
j, k Evans introduces a unitary basis consisting of certain complex
basis vectors e(1), e(2), e(3).
The elementary rules in the consequence of that coordinate transform are
summed up in
Appendix 1.
I shall refer to formulas in Appendix 1
by the equation labels (A. ..).
Vectors are denoted by bold face letters, e.g. the basis vectors i,
j, k. The letter i in light face is the imaginary unit.
In the course of the actual email discussion Evans referred to the book [9]
to justify his calculations in Appendix 2. He wrote:
So I give some quotes of that pages in Appendix 3. It will turn out that Evans' definition given in his REFUTATION is completely incompatible to Jackson's description of circular polarization.
Appendix 4 contains some simple questions to M. Evans on the basis of Appendix 3 he refused to reply to in the email discussion.
The first elementary error in Bruhn's claims occurs in his equations equs. (2.3) and (2.4) .
Check 1
Let's quote some eqs. of my paper [5]. Due to the literature
(e.g.
[7; p.188], [8; p.702 f.]) a vector
B = i Bx + j By
of left (+ = L) and right (− = R) circular polarization around the z-axis (direction k)
is given by choosing
(2.1)
Bx = B0 cos Φ
and
By = B0 sin Φ .
Then due to Evans' basic equations (A.3) and (A.5)
we obtain the components of B
relative to the cyclic basis of the vectors e(r) (r=1,2,3):
(2.3)
BR(1)
= e(1) B(0) eiΦ,
BR(2)
= e(2) B(0) e−iΦ
and
(2.4)
BL(1)
= e(1) B(0) e−iΦ,
BL(2)
= e(2) B(0) eiΦ
Result 1
There is no doubt about it, the equations
(2.3) and (2.4)
describe right
and left handed circular polarization correctly.
It is easy to show that Bruhn has made an elementary blunder because when we add his equations equs. (2.3) and (2.4) we obtain
BL(1) + BR(1)
= B(0) e(1)
(eiΦ + e−iΦ)
= B(0) 2−1/2 (i − i j)
(eiΦ + e−iΦ)
(1)
= B(0) 2−1/2 (i − i j) cos Φ
(2)
However, it is well known that the sum of left and right circular polarization is linear polarization. Bruhn’s equ. (2) is still circular polarization.
Check 2
Preliminary remark (of minor importance):
In (2) a factor 2 is missing. Hence we have
correctly
BL(1) + BR(1)
= B(0) 21/2 (i − i j) cos Φ
(2')
We shall use (2') instead of (2) below.
Due to the rule
(A.7),
a(2) = a(1)*, we obtain from (2')
BL(2) + BR(2)
= B(0) 21/2 (i + i j) cos Φ
while
B(3) = 0 holds by assumption.
Hence from
B = B(1) + B(2)
+ B(3)
(cf. (A.2)) we obtain
B
= 2 B(0) 21/2 i cos Φ
= i 2 B0 cos Φ .
Result 2
B is a real vector in constant direction i
oscillating proportionally to cos Φ. Hence B is clearly linear polarized.
The correct way to represent left and right
circular polarization is as follows
BL(1)
= 2−1/2 (Bx i − i By j)
eiΦ
(3)
BR(1)
= 2−1/2 (Bx i + i By
j) eiΦ
(4)
Check 3
The superscript (1) of the notations BL(1)
and BR(1) in the equs. (3) and (4)
means that the e(1)-components of the vectors
BL and BR will be defined by the right sides
of the equs. (3) and (4). Hence e.g. the right side of equ. (3) must be parallel to the basis vector
e(1) (cf. equs. (1) and (2), where the
e(1)-component
of BL + BR is defined by a vector
| | i − i j, i.e. | | e(1)).
Therefore the equs. (3) and (4) would imply
Bx i + i By j | |
i + i j,
i.e. Bx = By. The choice in my article [5; (2.1)] which Evans is referring to
(or also Jackson's book [9; (7.21)]) yields
Bx = B0 cos Φ
and
By = B0 sin Φ ,
Bx = By hence implies cos Φ = sin Φ.
That contradicts the variability of Φ and is impossible.
Result 3
The definition of
BL(1) and BR(1)
by the equs. (3) and (4) is inconsistent.
Add (3) and (4) to obtain
BL(1) + BR(1)
= 21/2 Bx i eiΦ
(5)
which is linear polarization as required.
Check 4
By an argumentation analogously to
Check 3.
we see that
for Bx ≠ 0 equ. (5) would imply
i − i j | | i
which is a contradiction, regardless of the rest of Evans' claim.
Result 4
Equ. (5) is inconsistent.
From equ. (3) we see that the left c.p. wave is
BL(1) = 2−1/2 (Bx cos Φ i + By sin Φ j) (6)
From equ. (4) we see that the right c.p. wave is
BR(1) = 2−1/2 (Bx cos Φ i − By sin Φ j) (7)
Equ. (6) is Bruhn’s equ. (4.2) and equ. (7) is Bruhn’s equ. (4.1).
Check 5
By an argumentation analogously to
Check 3.
we see that
(6) would imply
i − i j | |
i cos2Φ + j sin2Φ
which is a contradiction since the left side has an imaginary part while
the right side is real.
An analoguos argumentation holds for equ. (7).
Concerning Evans' last remark we quote the equations (4.1-2)
from our refutation [5]:
(4.1)
BR = B0 (i cos Φ + j sin Φ)
and
(4.2)
BL
= B0 (i cos Φ − j sin Φ).
Equ. (4.1) describes a right polarized wave and (4.2)
describes a left polarized wave.
Of course, the equations (4.1-2) are in accordance with the literature (cf. [7; p.188], [8; p.702 f.]).
Result 5
The equs. (6) and (7) are inconsistent.
This shows that my equations (3) and (4) give Bruhn’s own definitions of left and right handed c.p. in his equs. (4.1) and (4.2).
Check 5
As I have just shown Evans' equs.
(3) and (4)
are erroneous while my
(4.1) and (4.2) are correct since being
in accordance with the literature.
Result 6
Bruhn’s equs. (4.1) and (4.2) therefore contradict Bruhn’s equs. equs. (2.3) and (2.4), because when we add Bruhn’s equs. (4.1) and (4.2) we obtain linear polarization, but when we add equs. equs. (2.3) and (2.4) we obtain circular polarization.
Check 7
As we have remarked above the equs. (4.1) and (4.2)
give right and left polarization in accordance with the literature.
And the equations
(2.3)
BR(1)
= e(1) B(0) eiΦ,
BR(2)
= e(2) B(0) e−iΦ
and
(2.4)
BL(1)
= e(1) B(0) e−iΦ,
BL(2)
= e(2) B(0) eiΦ
are nothing but
the components of BR and BL
relative to the basis e(1), e(2),
as can be shown by an elementary calculation. Hence there cannot be any contradiction
between these equations.
Result 7
An elementary calculation would show no contradiction
between these equations.
The glaring error in Bruhn’s claims occurs in
his equ. (4.5), were he asserts, that for linear polarization:
B(3) = ? + 21/2 B(0) k
(11)
Check 8
Evans' quotation of equ. (4.5) is incorrect: The correct quote is
(4.5)
B(3) = 0
OR
B(3) = + 21/2 B(0) k
Hence (4.5) is valid, since Evans' assures the first alternative
of that OR-statement to be true.
Result 8
Evans' Claim 8 is due to an incorrect quotation.
The B Cyclic theorem always applies to one sense of polarization.
Check 8
That claim is at least dubious. Since in 1994 Evans had declared in [2; p.69];
"We assert therefore that in classical
electrodynamics there are three components B(1),
B(2) and
B(3) of a travelling plane wave in vacuo.
These are interrelated in the circular basis by equation
[2; (2)]. The third component, the ghost field
B(3)
= B(1) × B(2) / (i B(0))
= B(0) k
is real and independent of phase."
Equ. [2; (2)] are Evans’ cyclic equations that were extended herewith by M. Evans himself to «waves in vacuo» [2, p. 69] without any restriction. And lateron he did never qualify that statement. Thus: Evans’ cyclic equations could be thought to be valid for the superposition of circularly polarized plane waves too. This was what I have checked in my refutation [5] − with negative result.
Now in his "REFUTATION" [6] from 2004 Evans declares as a reply on my provocing paper [5] with restrictive intention
"The B Cyclic theorem always applies to one sense of polarization."
i.e. Evans' cyclic equations do not hold for linear polarization as a superposition of right and left handed circular polarization.
Result 9
Now, in 2004, M. Evans agrees with the result of my refutation [5].
All claims in Myron W. Evans' "REFUTATION" [6] have turned out to be erroneous or dubious at least. Therefore publications of that author should be read with greatest caution and scepticism.
[1] M.W. Evans: The elementary static magnetic field of the photon, Physica B 182 (1992) 227-236.
[2] M.W. Evans: The photomagneton B^(3) and its longitudinal ghost field B(3) of electromagnetism, Foundations of Physics Letters, Vol. 7, No. 1 (1994) 67 - 74.
[3] M.W. Evans: The Enigmatic Photon, Vol. 5, Kluwer Academic Publishers 1999, ISBN 0-7923-5792-2
[4] M.W. Evans e.a. : Explanation of the Motionless Electromagnetic Generator (MEG) with O(3) Electrodynamics; Foundations of Physics Letters, Vol. 14 No. 1 (2001)
[5]
G. W. Bruhn: Refutation of Myron W. Evans’ B(3) field hypothesis
http://www2.mathematik.tu-darmstadt.de/~bruhn/B3-refutation.htm
[6]
M.W. Evans:
REFUTATION OF THE CLAIMS OF G. BRUHN (handwritten)
http://www2.mathematik.tu-darmstadt.de/~bruhn/abruhnrefutation.pdf
[7] W. Demtröder: Experimentalphysik 2; 2. Auflage, Springer Verlag 2002, ISBN 3-540-65196-9
[8] E. Schmutzer: Grundlagen der Theoretischen Physik Teil 1; 2. Auflage, BI Verlag 1989, ISBN 3-411-03145-X
[9] J.D. Jackson: Classical Electrodynamics; 3. Ed. , Wiley 1989, ISBN 0-471-30932-X
Circular basis (Cartesian unit vectors i, j, k, imaginary unit i)
:
(A.1)
e(1)
= (i − i j)/21/2,
e(2)
= (i + i j)/21/2,
e(3)
= k .
Coordinate representations of all vectors a:
(A.2) ax i + ay j + az k = a = a(1) e(1) + a(2) e(2) + a(3) e(3)
Transformation rule for coordinates
(A.3) a(1) = 2−1/2 (ax + i ay), a(2) = 2−1/2 (ax − i ay), a(3) = az.
(A.4) |a(1)|2 +|a(2)|2 +|a(3)|2 = ax2 + ay2 + az2 = |a|2 .
Vector components of a relative to the circular basis
(A.5) a(1) = a(1) e(1), a(2) = a(2) e(2), a(3) = a(3) e(3).
The suffix * denotes the conjugate complex of the quantity where it is attached.
(A.6) e(1)* = e(2), e(2)* = e(1), e(3)* = e(3)
(A.7) a(1)* = a(2), a(2)* = a(1), a(3)* = a(3)
(A.8) a(1) = a(2)*, a(2) = a(1)*, a(3) = a(3)*.
(A.9) e(1) × e(2) = ie(3)*, e(2)× e(3) = i e(1)*, e(3)× e(1) = i e(2)*.
Remark The rules (A.1-8) have an important consequence that was not explicitly pointed out in Evans' book [3]: The vector coordinates ax, ay and az have to be reals, in other words, the vectors a subject to the above rules must be real: Due to (A.2) and (A.7) we obtain
a* = a(1)* + a(2)* +a(3)* = a(2) + a(1) +a(3) = a
which implies the reality of the coordinates ax, ay, az by using (A.2) again.
(Copy of the handwritten original [6])
The relevant e-mail posting by G. Bruhn is appended. Bruhn posted it without my knowledge, and apparently it was an unrefereed document. Bruhn refers to none of my recent work which is now universally acclaimed and accepted. Here I comment on Bruhn's posting section by section.
Section 1
This is merely a quote by Bruhn of some of my earliest work on B(3), almost a decade ago.
Section 2
The first elementary error in Bruhn's claims occurs in his equations
equs. (2.3) and (2.4).
It is easy to show
that Bruhn has made an elementary blunder because when we add his
equations
equs. (2.3) and (2.4)
we obtain
BL(1) + BR(1)
= B(0) e(1)
(eiΦ + e−iΦ)
= B(0) 2−1/2 (i − i j)
(eiΦ + e−iΦ)
(1)
= B(0) 2−1/2 (i − i j) cos Φ
(2)
However, it is well known that the sum of left and right circular polarization is linear polarization. Bruhn’s equ. (2) is still circular polarization.
The correct way to represent left and right
circular polarization is as follows:
BL(1)
= 2−1/2 (Bx i − i By
j) eiΦ
(3)
BR(1)
= 2−1/2 (Bx i + i By
j) eiΦ
(4)
Add (3) and (4) to obtain
BL(1) + BR(1)
= 21/2 Bx i eiΦ
(5)
which is linear polarization as required.
In fact I have mentioned the chirality question in my writings many times (e.g. Adv. Chem. Phys. Vol. 85). This shows that Bruhn is almost completely ignorant of my work. The rest of Bruhn’s claim is sequentially erroneous, and furthermore, contains other elementary blunders.
Section 3
In this section, Bruhn quotes my well known B Cyclic Theorem.
Section 4
From equ. (3) we see that the left c.p. wave is
BL(1) = 2−1/2 (Bx cos Φ i + By sin Φ j) (6)
From equ. (4) we see that the right c.p. wave is
BR(1) = 2−1/2 (Bx cos Φ i − By sin Φ j) (7)
Equ. (6) is Bruhn’s equ. (4.2) and equ. (7) is Bruhn’s equ. (4.1).
This shows that my equations (3) and (4) give Bruhn’s own definitions of left and right handed c.p. in his equs. (4.1) and (4.2).
Bruhn’s equs. (4.1) and (4.2) therefore contradict Bruhn’s equs. equs. (2.3) and (2.4), because when we add Bruhn’s equs. (4.1) and (4.2) we obtain linear polarization, but when we add equs. equs. (2.3) and (2.4) we obtain circular polarization.
These errors already make nonsense of Bruhn’s unrefereed claim, but his main error is to confuse what is meant by B(3). I have written many times that B(3) is equal and opposite for left and right handed circular polarization, and for this reason vanishes in linear polarisation. Mathematically:
BR(3)
= − i/B(0)
BR(1)
× BR(2)
= . . .
= i2
B(0) k
= − B(0) k
(8)
BL(3)
= − i/B(0)
BL(1)
× BL(2)
= . . .
= − i2 B(0) k =
B(0) k
(9)
Thus:
BR(3) = − BL(3) (10)
The glaring error in Bruhn’s claims occurs in his equ. (4.5), were he asserts, that for linear polarization:
B(3) = ? + 21/2 B(0) k (11)
The reason for the erroneous equ. (11) appears to be confusion about what is meant by B(3) . The latter is well-defined in my work as existing for one photon. One photon is either left handed, in which case we obtain equ. (9) or right handed, in which case we obtain equ. (8). If we superimpose one left handed photon with one right handed photon we obtain
B(3) = BR(3) + BL(3) = 0.
The B Cyclic theorem always applies to one sense of polarization.
Therefore the claim by Bruhn is false, and unreasonable, i.e. it is made in ignorance of the literature.
Firstly a quote from an Evans' email:
. . . the most general homogeneous plane wave . . .
E(x,t) = (e1 E1 + e2 E2) e− iΦ where Φ = ωt − k·x (7.19)
with the Cartesian basis vectors e1,e2,k, c.f. Fig. 7.1, p.297 (identical with the usual Cartesian basis denoted by i, j, k).
We should realize that (7.19) is not the original wave vector which is real: The imaginary part was supplemented in order to get arithmetical advantages and has no physical meaning.
If E1 and E2 have the same phase (7.19) represents a linearly polarized wave. . . .
. . . circular polarization. Then E1 and E2 have the same magnitude, but differ in phase by 90°.
E(x,t) = E0 (e1 + i e2) e− i Φ where Φ = ωt − k·x (7.20)
. . . while e1 and e2 are in the x and y directions, respectively. Then the components of the actual electric field, obtained by taking the real part of (7.20), are
Ex = E0 cos Φ
(7.21)
Ey = + E0 sin Φ
... For the upper sign (e1 + i e2)
the rotation is counterclockweise
when the observer is facing into the oncomming wave.
This wave is called left circularly polarized in optics. ...
For the lower sign (e1 − i e2)
the rotation of E is clockwise when looking into the wave is right circularly
polarized (optics) ...
. . . We introduce the complex orthogonal unit vectors:
e+ = 2−1/2 (e1 + i e2) (7.22)
. . . Then a general representation, equivalent to (7.19), is
E = (E+ e+ + E− e−) e− iΦ (7.24)
where E+ and E− are complex amplitudes.
Examples
For the pupose of comparison with Evans' formulas we replace Jackson's notation with that one
of Evans:
e1 → i,
e2 → j,
e− → e(1),
e+ → e(2),
E → B, . . .
A linearly polarized wave is given if the quotient B+/B−
is real, in which case, by changing the coordinate system, we can attain the
standard form
Blin = B0 i e− iΦ
with some real constant B0.
Circularly polarized waves can be described by means of the complex basis vectors
e(1) and e(2):
BL(1)
= B0 e(1) e− iΦ
is Jackson's standard form of a left circularly polarized wave, strictly speaking,
its e(1)-component, while
BR(2) = B0 e(2) e− iΦ
is Jackson's standard form of a right circularly polarized wave, more exactly, its
e(2)-component. The e(1)-component of
BR can be obtained by
taking the conjugate complex expression, i.e.
BR(1)
= B0 e(1) eiΦ .
For a comparison we have to take into account that the last representations are not
the original real wave vectors but are the result of complex supplementation.
However, it is
easy to reconstruct the original physical wave vectors: We merely have to take the
corresponding real parts.
By doing so we obtain
Blinphys
= B0 i cos Φ for linear polarization,
BLphys
= Re {B0 e(1) e− iΦ}
= B0 (i cos Φ − j sin Φ)/21/2
for left circular polarization
and
BRphys
= Re {B0 e(2) eiΦ}
= B0 (i cos Φ + j sin Φ)/21/2
for right circular polarization.
We have to compare Jackson's standard forms of polarized waves with that
ones given by Evans in his
"REFUTATION" equs. (3-5):
Evans
Jackson
BL(1)
= 2−1/2 (Bx i − i By
j) eiΦ ,
BL(1)
= B0 e(1) e− iΦ
BR(1)
= 2−1/2 (Bx i + i By
j) eiΦ ,
BR(1)
= B0 e(1) eiΦ .
Let's quote Evans again:
«. . . my definition of circular polarization is the same as that in a standard text such as J. D. Jackson, "Classical Electrodynamics" (Wiley third edition, 1999, page 299, eq. (7.20)).»No, Dr. Evans, not at all. There is a considerable disagreement between Evans' and Jackson's formulas. Possibly, Evans' formulas are erroneous due to rather simple errors. However, Evans intended to give a refutation of my calculations. For that purpose Evans should have proceeded much more carefully.
Additionally I can state that my formulas (2.3) and (2.4) for circular polarization completely agree with the Jackson's formulas above.
Instead of replying to the questions Evans broke off the discussion:
Quotation from Evans' email:
1.1) Do you admit, that the physical vectors Blin for linear polarization,
BL for left-handed and BR for right-handed polarization
are real vectors?
BL = B0
(i cos Φ− j sin Φ)
BR
= B0 (i cos Φ + j sinΦ)
(Φ = ωt − k·x)
Blin
= 2 B0 i cos Φ
(Y / N)
1.2)
Due to Jackson's equs. (7.19) and (7.20)
(J.D. Jackson: Classical Electrodynamics 3.Ed. 1999)
(with exchange of characters
E → B and e1,
e2 → i, j), e.g.
B(x,t)
= B0 (i + i j) e− iΦ
(Φ = ωt − k·x)
(7.20)
the Jackson-vectors have nonvanishing imaginary parts, i.e.
Jacksons' equs. do not agree with the
above real physical representation
formulas in 1.1.
(Y / N)
1.3) Can you explain the physical meaning and origin of these imaginary parts?
(Y / N)
If Y, please, give an explanation.
2) Why just these imaginary parts? I know other ones that would fit.
3.1) Do you know that all physical vectors a that fulfil your
basic rules
in Vol. 5 of your photon-books must be real?
a = a*
(Y / N)
3.2) Which of the vectors B defined in 1.1 or 1.2 could fulfil
the Evans basic rules?
(1.1 / 1.2 / both)
4) Consider three important polarized waves using the real representations
of the wave vector B according to
Jackson (7.21):
Left circular:
(L)
Bx = B0 cos Φ,
By = − Bx = − B0 sin Φ
Right circular: (R)
Bx = B0 cos Φ,
By = + Bx = + B0 sin Φ
Linear in x-dir.: (lin) Bx
= 2 B0 cos Φ,
By = 0
Addition yields (L) + (R) = (lin).
Now insert that into Evans' equs. [Enigm.Photon Vol 5; ((1.1.6)]
(cf. Evans basic rule A.3)
for circular vector coordinates which are
B(1) = (Bx − i By)/sqr(2),
B(2) = (Bx + i By)/sqr(2)
to obtain
(L)
B(1) = B0 e−iΦ/sqr(2),
B(2) = B0 e+iΦ/sqr(2),
(R)
B(1) = B0 e+iΦ/sqr(2),
B(2) = B0 e−iΦ/sqr(2),
(lin) B(1) = B(2) = sqr(2) B0 cos Φ.
That result contradicts Evans' formulas in his
"REFUTATION" equs. (3-5)
who claims
(L)
B(1)
= (Bx i − i By j) eiΦ/sqr(2),
(R)
B(1)
= (Bx i + i Byj) eiΦ/sqr(2),
(lin)
B(1) = sqr(2) Bx i eiΦ.
One should have [Enigm.Photon Vol 5; (1.1.5)]
(cf. A.5)
B(1) = B(1) e(1)
e.g. in the case (lin) we obtain the different results for B(1):
sqr(2) e(1)
B0 cos Φ
and
sqr(2) Bx i eiΦ
= sqr(2) i B0 eiΦ cos Φ
respectively.
Thus, there is a contradiction within Evans' original formulas.
Should there exist "ghosts" that have been produced by using
the "Jackson-method" of complex supplementation?
(Y / N)
If N: Where is the error? (???)